Mapa Sapling Learning At a certain temperature the Ko for th

Mapa Sapling Learning At a certain temperature, the Ko for the decomposition of HS is 0.752. Initially, only H2S is present at a pressure of 0.244 atm in a closed container. What is the total pressure in the container at equilibrium? atm O Previous Gve Up & View Solution Check Answer 0 Next -H Exit ?Hint

Solution

     H2S(g) -------------- H2(g) + S(g)                             Kp = 0.752

0.244 atm                   0           0

   - x                            +x        +x

0.244 -x                     +x           +x

Kp = PH2 xPS/PH2S

0.752 = x*x/(0.244 -x)

0.183 - 0.752 x = x^2

x^2 + 0.752 x - 0.183 =0

for solving the equation

x=0.194

At equilibrium

Partial pressure of H2S= 0.244 - 0.194 = 0.05 atm

partial pressure of H2= 0.194 atm

partial pressue of S= 0.194 atm

Total pressure at equilibrium = 0.05 + 0.194+ 0.194 = 0.438 atm