Processor A has a CPI 12 and a clock rate o2 GHz Processor B

Processor A has a CPI 1.2 and a clock rate o(2 GHz. Processor B has a CPI of 2.2 and a dock rate of 4 GHz. Both Processors implement the same instruction set Determine the time per instruction for each processor and write it in the correct spot. Which processor is faster? How many times faster is It than the slower processor? Show your work! Processor A time per instruction _____ Processor B time per instruction _____ Which is faster? How many times faster?

Solution

For Processor A has a CPI 1.2 and a clock rate of 2 GHz.
SO instructions per second = 2 GHz / 1.2 = 1.66*10^9

For Processor B has a CPI 2.2 and a clock rate of 4 GHz.
SO instructions per second = 4 GHz / 2.2 = 1.81*10^9

So B has the highest performance. and 0.15*10^9 Time Faster than Processor A