A 10 inch diameter hole is drilled on the centerline of a lo

A 1.0 inch diameter hole is drilled on the centerline of a long, flat steel bar that is 1/2 inch thick and 4 inches wide. The bar is subjected to a tensile load of 30,000 lb. Calculate the average stress in the plane of the reduced cross section and the maximum tensile stress immediatle adjacent to the hole.

Solution

Given that

W= 4 inch= 10.16 cm

H= 0.5 inches= 1.27 cm

F= 30000 lb = 133446.64885N

( 1kg = 2.204622622 lbd

d= 1inch = 2.54 cm

A=h ( w-d)

=1.27(10.16- 2.54)

= 9.6774cm^2

Now stress =F/A

= 133446.64885/(9.6774*10^-4)

= 137.8951462Mpa

Now maximum tensile streets =stress (nom.)*k

*(K is not given)