Given triangle ABC where side a is opposite angle A side b i

Given triangle ABC, where side a is opposite angle A, side b is opposite angle B, and side c is opposite angle C, and a =10 , b=20 , and C =110 find the length of c.

Problem 1: Given triangle ABC, where side a is opposite angle A, side b is opposite angle B, and side c is opposite angle C, and a-10, b-20, and C-110 find the length of c. (5 points) C

Solution

a = 10 , b = 20, C = 110

applying law of cosines to find length of c

c^2 = 10^2 + 20^2 - 2(10)(20) cos 110

c = 25.24

length of c is 25.24