Given the value of the equilibrium constant K for equation a

Given the value of the equilibrium constant (K) for equation (a), calculate the equilibrium constant for equation (b). (a) 02(g)303(g) Kc= 1.11 x 10-9 (b) 302(g)203(g) Kc (Enter your answer in scientific notation) X10

Solution

when reaction is multiplied by factor , K is rasied to poer of that factor

O2 <---> 2/3O3 , Kc = 1.11 x 10^ -9

3 ( O2 <---> 2/3O3) Kc new = ( 1.11 x 10^ -9) ^ 3

3O2 (g) <---> 2O3 (g) , Kc = 1.37 x 10^ -27