In the circuit represented by the figure below the bulb B ha
Solution
Ans
The conducting wire in the given circuit has excess electrons.These electrons distribute themselves
in a way that the mutual repulsive force between two electrons is minimum. Now when the block of
charge is placed between the gap, the positive part of the block will induce the electrons in the segment
of the wire to the right of the gap.
As the electric field due to positive chagein the block is +ve i.e in nature, this force will also push away
the positive charges from the block to c and attract the electrons towards it.
When the block of charges ( separated by non-conducting wood) is placed inside the wire,
the negative part will induce repulsion on the wire connected with the left segment where as
the postive charge will induce the other segment.The forces will make the free electrons move.
Electrons will be repelled from the negative chrage and will be attracted towards the positive charge.
But this movement will be internal. As the block has net charge zero and the conductor is
also neutral, the net force will also be zero.
