Subtract xx2 10x 25 x 42x 10Solutionxx2 10x 25 x42x

Subtract: x/x^2 - 10x + 25 - x - 4/2x - 10.

x/(x^2 - 10x + 25) - (x-4)/(2x -10)

factorise x^2 -10x +25 = x^2 - 5x -5x +25

= x(x -5) -5(x-5)

= (x-5)^2

So, x/(x -5)^2 - (x-4)/2(x- 5)

(1/(x-5)[ x/(x-5) - (x -4)/2 ]

(1/(x-5))[ (2x -(x-4)(x-5)]/2(x -5)

(1/(x -5))[ 2x - (x^2 -9x +20)]/2(x-5)

(1/(x -5))[ -x^2 +11x -20]/2(x-5)

( -x^2 +11x -20)/2(x -5)^2