14 Lee has twice as many dimes as nickels and two more quart

14. Lee has twice as many dimes as nickels and two more quarters than dimes. The total value of the coins is $8.00. Find the number of coins of each denomination.

Let

Nickel=x

Dime =2x

Quarer = 2x+2

since total worth is 8, set up equation as

0.05x +0.1(2x)+0.25(2x+2)=8

0.05x +0.2x+0.5x+0.5=8

0.75x=8-0.5

0.75x=7.5

x=75/7.5

x=10

Therfore,

Nickel=10

Dime =20

Quarer = 22

14. Lee has twice as many dimes as nickels and two more quarters than dimes. The total value of the coins is $8.00. Find the number of coins of each denominatio

14 Lee has twice as many dimes as nickels and two more quart

Solution

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