Write a program tart has 2 factors One unction computes the
Solution
//Program calulate interests
//Header file required to compute the expression
 #include <iostream>           // input output header
#include<math.h>           //math function header
 void quarter(int p,int r);       //function declaration to compute qurter wise expression
 void continuos(int p,int r);       //function declaration to continuos qurter wise expression
 using namespace std;              
 int main()                        //main function begins
 {
 int p,r;                                    //varible declarations
cout<<\"Enter any Principal amount: \"<<endl;        //prompt for principle amount value
 cin>>p;                                        //read pvalue
 cout<<\"Enter Rate of interest: \"<<endl;        //prompt for rate of interest in decimal
 cin>>r;                                        //read r
 quarter(p,r);                           //calling function qurter
 continuos(p,r);                           //calling function continuos
return 0;
 }
 void quarter(int p,int r)               //function defination
 {
    double y1,y2,y3,y4,y5;
    double d=(double)r/100;       //convert rate into fraction
  
      y1= p*pow((1+d/4),4*1)   ;   //A = P (1 + r/n) ^nt, t indicates time year wise, n indicates how many times compond per year,r means rate ,p means principal
    
      y2= y1*pow((1+d/4),4*1);  
      y3= y2*pow((1+d/4),4*1);  
      y4= y3*pow((1+d/4),4*1);  
      y5= y4*pow((1+d/4),4*1);  
      cout << \"Quarterly Compound Intereset Rates Year wise \" <<endl;
      cout << \"Year1 : \" <<y1<<endl;
      cout << \"Year2 : \" <<y2<<endl;
      cout << \"Year3 : \" <<y3<<endl;
      cout << \"Year4 : \" <<y4<<endl;
      cout << \"Year5 : \" <<y5<<endl;
    
   
 }
 void continuos(int p,int r)               //function defination
 {
    double y1,y2,y3,y4,y5;
    double d=(double)r/100;
  
      y1= p* exp (d*1);           //A = P * e ^rt ,e means exponent,r means rate ,t means time in year format
    
      y2= y1* exp (d*1);  
      y3= y2* exp (d*1);  
      y4= y3* exp (d*1);  
      y5= y4* exp (d*1);  
      cout << \"Continuos Compound Intereset Rates Year wise \" <<endl;
      cout << \"Year1 : \" <<y1<<endl;
      cout << \"Year2 : \" <<y2<<endl;
      cout << \"Year3 : \" <<y3<<endl;
      cout << \"Year4 : \" <<y4<<endl;
      cout << \"Year5 : \" <<y5<<endl;
    
   
 }
 Output :
Enter any Principal amount:
 5000
 Enter Rate of interest:
 5
 Year1 : 5254.73
 Year2 : 5522.43
 Year3 : 5803.77
 Year4 : 6099.45
 Year5 : 6410.19
 Year1 : 5256.36
 Year2 : 5525.85
 Year3 : 5809.17
 Year4 : 6107.01
 Year5 : 6420.13


