A solution is created by dissolving 100 grams of ammonium ch

A solution is created by dissolving 10.0 grams of ammonium chloride in enough water to make 265 mL of solution. How many moles of ammonium chloride are present in the resulting solution?

Solution

Moles of ammonium chloride = mass of ammonium chloride / molar mass of ammonium chloride

= 10g / 53.491 g/mol

= 0.187 moles

Moles of ammonium chloride = 0.187