At 298 K the Henrys law constant for oxygen is 000130 Matm A

At 298 K, the Henry\\\'s law constant for oxygen is 0.00130 M/atm. Air is 21.0% oxygen.

At 298 K, what is the solubility of oxygen in water exposed to air at 1.00 atm?

At 298 K, what is the solubility of oxygen in water exposed to air at 0.897 atm?

If atmospheric pressure suddenly changes from 1.00 atm to 0.897 atm at 298 K, how much oxygen will be released from 4.90 L of water in an unsealed container?

Solution

(1-0.897)*0.0013M/atm*4.9*0.21 molefraction of air = 0.0001377 moles of oxygen released