A quadratic function has its vertex at the point 0 6 The fun

A quadratic function has its vertex at the point (0, 6). The function passes through the point (7, -4). When written in vertex form, the function is f(x) = a(x - h)^2 + k, where: a =. h =. k = .

Solution

Y=a(x-h)²+k

is standard form, and vertex is (h,k).

Using your given vertex, Y=a(x-0)²+6

Other given point on the graph is (7, -4), so put this into the equation and find a.

-4=a*7 ²+6

So a=-10/49

The equation is y=(-10/49)x²+6