A 0477 mol sample of O2 gas has a volume of 106 L at a certa

A 0.477 mol sample of O2 gas has a volume of 10.6 L at a certain temperature and pressure. If all this O2 were converted to ozone (O3) at the same temperature and pressure, what is the ozone volume (in liters)? 3 O2(g) 2 O3(g)

Solution

0.477mole of O2 sample .

3 mole of O2 forms 2 mole of O3

So 0.477 mole of will form 0.318 mole of O3

Now V1/n1 = V2/n2

V1 = 10.6 L , n1 = 0.477 , n2= 0.318 , V2 = we have to find

V2 = (10.6*0.318)/0.477 = 7.0667 Litre

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