What is the total charge on the semicircle What is the y com
What is the total charge on the semicircle?
What is the y component of the electric field at the origin?
Solution
1. considering a d@ angle part of arc at angle @.
then charge density lambda = - 1.39@
width of part of this arc = R d@
charge on that part, dq = - 1.39 R @ d@
integrating,
q = - 1.39 R @^2 /2
where @ is from 0 to pi.
q = - 1.39 (0.394) (pi ^2 - 0 )/ 2 = - 0.274 pi^2 uC or - 2.7 uC
2. for this part, field at centre.
dE = k dq / R^2 = 1.39 k R @ d@ / R^2
dE = 1.39 k @ d@ / R
y - component, dEy = dE sin@
dEy = (1.39 x 10^-6 x 9 x 10^9 / 0.394 ) @ sin@ d@
dEy = 31751.27 @ sin@ d@
inetegrating,
Ey = 31751.27 ( sin@ - @cos@)
where @ is from 0 to pi
Ey = 31751.27 [ sinpi - pi cospi - sin0 + 0 cos0 ]
Ey = 31751.27 x pi = 99750 N/C
