Explain each step and why you used each equation Refer to a

Explain each step and why you used each equation. Refer to a steam table chart if needed

5 kg\'s of water at 1.0 MPa and 350 degree C enters a nozzle with negligible velocity. The water leaves at 500 m/s, 0.2 MPa and 100 degree C. How much heat transfer must occur for this to be possible?

Solution

Given: mass(m)=5kg/s

         inlet pre(P1)= 1.0MPa=1000KPa

       inlet temperature(T1)=350 C=623K

       inlet velocity(V1)= 0

outlet pre(P2)=.2MPa= 200KPa

outlet velocity(V2)= 500m/s

outlet temp(T2)= 100 C= 373K

nozzle is treated as a steady flow device

therefore we apply steady flow energy equation to solve this.

specific heat of water(Cp)= 4.187kj/kgk

enthalpy= h

h1+V1^2/2000+Q=h2+V2^2/2000+W

W=0;

V1=0

Cp T1+V1^2/2000+Q=Cp T2 +V2^2/2000+W

4.187*623+Q=4.187*373+500^2/2000

Q=67267.499 KJ/Kg

Q= m*67267.499= 5* 67267.499

Q= 337.83 KW