Express the concentration of a 00580 M aqueous solution of f

Express the concentration of a 0.0580 M aqueous solution of fluoride, F–, in mass percentage and in parts per million. Assume the density of the solution is 1.00 g/mL.

Solution

We assume that we have exactly 1 L of the solution.

Now,

(1 L) x (0.0580 mol F^- / L) x (18.9984 g F^-/ 1 mol F^-) = 1.1019 g F^-

(1000 mL ) x (1.00 g/mL) = 1000 g solution

In mass perccentage we have,

(1.1019 g F^- ) / (1000 g solution) x 100 % = 1.1019 x 10^-3 x 100 % = 0.110 %

In parts per million we have,

1.1019 x 10^-3 = 1101.9 x 10^-6 = 1101.9 ppm F^- =1102 ppm F^-