If the radius of a planet is r3765 miles and the angle at th

If the radius of a planet is r=3765 miles and the angle at the planet\'s center is Upper A equals 89 degrees 3 primeA=89°3 find the shortest distance between its moon and the surface of the planet. The distance between its moon and the surface of the planet is approximately nothing miles. (Round to the nearest mile as needed).

Given that the angle is at the center of the planet, so the point associated with it is not on the surface. P is on the surface, but not closest to the moon. Use trigonometric properties to find the lengths of the sides of the triangle. Use the appropriate length and the radius to determine the distance.

The answer is not 5846 miles !

Solution

Question is asking to find the shortest distance between its moon and the surface of the planet.
Then your assumption is \" distance between its moon and the surface of the planet is approximately nothing miles.\"
Which is exactly same thing that we are asked to find.
So the answer will be approx NOTHING or you can say 0 miles.