Which of the following aqueous solutions should have the hig

Which of the following aqueous solutions should have the highest boiling point?

a) 0.50 m NaOH b) 1.0 m CH3CO2H c) 0.50 m CaCl2 d) 1.5 m C6H12O6 e) 1.0 m LiBr

As we know that

Elecvation in Boiling point = Kim

Here i = No. of ions which a Compound can Break

m = Molality

So for Highest Boliling Point

i*m should be Maximum

For NaOH

Product is 0.5*2

= 1

For CH3CO2H and C6H12O6 i = 1

therefore products are 1 and i.5

For CaCl2 i = 3

So Prodcut = 3*0.5

= 1.5

For LiBr i = 2

Therefore

PRODUCT = 1*2

= 2 MAXIMUM

Therefore

e option is Correct