Find the angle to the nearest degree between each pair of ve
Solution
11) A=<2,-3>
B=<5,2>
A*B =10-6= 4
|A| =sqrt(4+9)=sqrt(13)
|B|= sqrt(25+4) =sqrt( 29)
theta =arc cos (4)/(sqrt(13*29)
theta = arc cos (0.2059)= 78 degrees
13) A= <2,-3,1>
B=< 4, -2, -3>
A*B = 8+6-3=14-3=11
|A|=sqrt( 10)
|B|= sqrt(29)
theta =arc cos( 0.5872)
=54 degrees
