Give the 32bit floating point number single precision for th

Give the 32-bit floating point number (single precision) for the base ten number -2243.12. (Give answer in hex)

Solution

Single precision (32 bits):

Bit 31

Sign Bit = 1

0: +

1: -

Bits 30 - 23

Exponent Field = 10001010

Decimal value of exponent field and exponent = 138 – 127 = 11

Bits 22 - 0

Significant = 1 .00011000011000111101011

Decimal value of the significant = 1.0952734

32-bit floating point number (single precision) for the base ten number -2243.12 in Hexadecimal: C50C31EB

Decimal: -2243.1199