Suppose that you discover that RAM addresses 000C0000 to 000

Suppose that you discover that RAM addresses 000C0000 to 000C7FFF are reserved for a PC’s video adapter in a 32-bit computer. How many bytes of memory is this?

Solution

000C7FFF-000C0000 = 00007FFF

(00007FFF)₁₆ = (32767)₁₀

In a 32-bit computer, every 8 bit hex address represents 1 byte.

So Number of bytes = 32767