Please help Thank you 192 ft 68 82 6 The following figure is

Please help! Thank you.

19.2 ft 68 82 6. The following figure is a top view of a Delt.a Dart jet. (a) Find the dimensions of the wing. (b) Find the surface area of the wing.

Let us take the triangle as mentioned above,

draw an altitude up on side BC from the point A, name it as D,

Sum of the angles of a triangle is 180

So angle DAC+ angle ADC+ angle DCA= 80,

then we will get the values as below

angle DAC= 60

angle ADC=90

angle DCA= 30

Consider the triangle ABD

Cos 8= adjacent side/ hypotenuse

Cos 8= AD/AB

0.990268069= AD/19.2

AD= 19.0131469

Sin 8= BD/19.2

BD= 2.67212354

From the triangle ADC,

Tan 30= AD/ DC

0.577350269= 19.0131469/DC

DC= 32.93236 ft

From the right-angled triangle ADC

Area= (Base*height)/2

Area of triangle ADC= (DC*AD)/2= 313.073899 sq ft

Area of triangle ADB= (BD*AD)/2=25.4027387 sq ft

Area of triangle ABC= Area of triangle ADC+Area of triangle ADB

=338.4766 sq ft

This is the surface area.