A pump is used to transport water through a horizontal 6inch

A pump is used to transport water through a horizontal 6-inch diameter. pipe The pump is S3 degree middot efficient and increases the pressure horn point A to point B by 50 pst. I he velocity distribution in the pipe is defined by the parabola. V(r) = 6(23 - r^2) where \'\'r\" is the radius m inches and V Ins units of inches per second .What is the pump power (in units of horsepower)?

Solution

Power gained by a pump is expressed by P=p*Q*g*h or P=eQh where e is specific weight (e=p*g). Since head h = (P_2-P₁)/e . This gives Power = (P₂-P₁) * Q . Now Velocity = Flow ratega / area of flow this results in Q = 6 (23-3²)x22x3²/7=5832 now substitutino in Power equation P = difference in pressure x discharge = 50*5832 =291600 and since the efficiency is 83 percentage so factoring this would give the correct power .