PROBLEM IV A boiler acquired on January 2 at a cost of 31500
Solution
Answer
Straight Line Method working
A
Cost
$ 3,15,000.00
B
Residual Value
$ -
C=A - B
Depreciable base
$ 3,15,000.00
D
Life [in years]
20
E=C/D
Annual SLM depreciation
$ 15,750.00
Year
Book Value
Depreciation expense
Ending Book Value
Accumulated Depreciation
1
$ 3,15,000.00
$ 15,750.00
$ 2,99,250.00
$ 15,750.00
2
$ 2,99,250.00
$ 15,750.00
$ 2,83,500.00
$ 31,500.00
Answer----
Depreciation expense: Year 1 = $ 15,750
Depreciation expense: Year 2 = $ 15,750
Declining Balance Method working using twice the SLM rate:
A
Cost
$ 3,15,000.00
B
Residual Value
$ -
C=A - B
Depreciable base
$ 3,15,000.00
D
Life [in years]
20
E=C/D
Annual SLM depreciation
$ 15,750.00
F=E/C
SLM Rate
5.00%
G=F x 2
DDB Rate
10.00%
Year
Beginning Book Value
Depreciation rate
Depreciation expense
Ending Book Value
Accumulated Depreciation
1
$ 3,15,000.00
10.00%
$ 31,500.00
$ 2,83,500.00
$ 31,500.00
2
$ 2,83,500.00
10.00%
$ 28,350.00
$ 2,55,150.00
$ 59,850.00
Answer----
Depreciation expense: Year 1 = $ 31,500
Depreciation expense: Year 2 = $ 28,350
| A | Cost | $ 3,15,000.00 | ||
| B | Residual Value | $ - | ||
| C=A - B | Depreciable base | $ 3,15,000.00 | ||
| D | Life [in years] | 20 | ||
| E=C/D | Annual SLM depreciation | $ 15,750.00 | ||
| Year | Book Value | Depreciation expense | Ending Book Value | Accumulated Depreciation |
| 1 | $ 3,15,000.00 | $ 15,750.00 | $ 2,99,250.00 | $ 15,750.00 |
| 2 | $ 2,99,250.00 | $ 15,750.00 | $ 2,83,500.00 | $ 31,500.00 |


