Hypothesis Testing II You think th the average wait time at
Solution
Ans 31)
Assumed average wait time is 10 minutes and we are claiming that it is different than 10 minutes
hence null hypothesis is
H0: MeanP=10
And alternate hypothesis is
H1:MeanP=! 10 (=! means not equals to)
ANs 32)
t value will be calculated as (Sample Mean-MeanP)/standard error
Standard error will be calculated as sqrt[Sum(X_-MeanP)^2/(Sample Size)]
t-value=(6.6-10)/(3.781/sqrt(5))=-2.01
Ans 33)
t critical value for 5% significance and df=4 from table 2.776
if calculated t value < critical t value then we can not reject null hypothesis
Hence in this case we can not reject null hypothesis because 2.01<2.776
Therefore wait time is none other than 10 minutes
Ans 35)
p value from calculated t of -2.01 is 0.05799 which states that there are chances to have mean equal to 10 are 0.11479 for 2 tailed test as it can be higher or lower than 10
Hence for p<0.05 we cannot reject null hypothesis
