Find a f x and bgx such that hx fgx hx1sqrt3x7Solutionhx fg

Find a) f (x) and b)g(x) such that h(x)= (f)(g)(x)

h(x)=1/sqrt3x+7

Solution

h(x) = (f)(g)(x) = 1/sqrt (3x + 7)

Since in h(x) there are two function one is square root and other one is linear equation, So assuming

g(x) = 3x + 7

f(x) = 1/sqrt x

f(g(x)) = f(3x + 7) = 1/sqrt (3x + 7)

Find a) f (x) and b)g(x) such that h(x)= (f)(g)(x) h(x)=1/sqrt3x+7Solutionh(x) = (f)(g)(x) = 1/sqrt (3x + 7) Since in h(x) there are two function one is square

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