Suppose that you have a supply of a 25 solution of alcohol a
Solution
Your first question is incomplete:
I think the missing part is as follows
Q.Suppose that you have a supply of a 25% solution of alcohol and a 75% solution of alcohol. How many quarts of each should be mixed to produce 70 quarts that is 35% alcohol?
Ans:
alcohol + alcohol = alcohol
Let x=amount of 25% solution needed in the mix.
0.25x + 0.75(70-x) = 0.35*70
Multiplying both sides by 100 we get,
25x + 75*70 - 75x = 35*70
-50x = -40*70
x = 56 quarts (amount of 25% solution needed in the mix)
70-x = 14 quarts (amount of 75% solution needed in the mix)
| Q.Suppose that you have a supply of a 25% solution of alcohol and a 75% solution of alcohol. How many quarts of each should be mixed to produce 70 quarts that is 35% alcohol? Ans: alcohol + alcohol = alcohol Let x=amount of 25% solution needed in the mix. 0.25x + 0.75(70-x) = 0.35*70 25x + 75*70 - 75x = 35*70 |
