Find average value of the function over the given interval y

Solution

To do this you take the integral from 0 to 2 and divide by 2-0=2 First we need the integral of the function (x^3)/3-(3x^2)/2+x Next we input the values: (2^3)/3-(3(2)^2)/2+2-0+0-0=8/3-6+2=-4/3 then divide this by 2 we get the average value =-2/3