Answer the following questions for the parabola y x2 3x4 T

Answer the following questions for the parabola y = x2 + 3x-4. Then, choose the correct graph. Use decimals when needed. This parabola opens up or down? up The parabola\'s axis of symmetry is The parabola\'s vertex is at (1.5, -6.25) The parabola\'s y-intercept is at (0,-4) The parabola\'s -intercept(s) is/are (1,0),(-4,0) (Use a comma to separate T-intercepts if needed. If the parabola doesn\'t have any T-intercept, type DNE, meaning \"does not exist.\"

Solution

y=x²+3x-4

Here a=1 , b=3 and c=-4

Since a is positive so , the parabola opens up

Vertex, x=-b/2a= -3/2(1) = -3/2 =-1.5

y=(-1.5)²+3(-1.5)-4=-6.25

Vertex (-1.5,-6.25)

Axis of symmetry, x=-1.5

y intercept , x=0

y=0 + 0 -4 =-4

(0,-4)

x intercept

y=0

x²+3x-4=0

(x+4)(x-1)=0

x=-4 ,1

(-4,0),(1,0)