How do you do stoichiometry with two givens and an excess of

How do you do stoichiometry with two givens and an \"excess\" of one of the compounds?

\"With 1.010 g of NaOH and excess HCl, what mass of NaCl could be formed?\"

Solution

The balanced equation is

HCl + NaOH ----> NaCl + H2O

number of moles of NaOH = 1.010 g / 39.997 g/mol = 0.0253 mole

from the balanced equation we can say that

1 mole of NaOH produces 1 mole of NaCl so

0.0253 mole of NaOH will produce

= 0.0253 mole of NaOH *(1 mole of NaCl / 1 mole of NaOH)

= 0.0253 mole of NaCl

mass of 1 mole of NaCl = 58.4 g

so the mass of 0.0253 mole of NaCl = 1.48 g

Therefore, the mass of NaCl produced would be 1.48 g