A baby elephant is stuck in a mud hole To help pull it out g

A baby elephant is stuck in a mud hole. To help pull it out, game keepers use a rope to apply a force F_A, as part a of the drawing shows. By itself, however, force F_A is insufficient. Therefore, two additional forces F_B and F_C are applied, as in part b of the drawing. Each of these additional forces has the same magnitude F. The magnitude of the resultant force acting on the elephant in part b of the drawing is k times larger than that in part a. Find the ratio F/F_A when k = 1.82.

Solution

Here ,

for the net force on the on the elephant

FA + 2 * F * cos(22) = k * FA

FA + 2 * F * 0.927 = 1.82 * FA

0.82 * FA = 1.854 * F

F/FA = 0.442

the ratio F/FA is 0.442