Complete K CH 15 HWK part 2 Problem 1540 Solutionsince both

Complete K CH 15 HWK part 2 Problem 15.40

Solution

since both drugs and protein are in 1:1 ratio, the reactions are

The reaction is Drug(A)+ protein<-->Drug-protein and Drug(B)+ Protein <> Drug-B protein

Initial concentration of A= 2*10^-6M, a concentration of protein = 1.72*10^-6M

At equilibrium, concentration of drugA-protein complex= 1*10^-6M

Hence concentration of A at equilibrium= 2*10^-6-1*10^-6= 1*10^-6M

Concentration of protein equilibrium = 1.72*10^-6-1*10^-6= 0.72*10^-6 M

KC= [Drug-protein]/[Drug] [protein] = 1*10^-6/ (1*10^-6*0.72*10^-6) = 1.39*10⁶

at Equilibrium, concentration of drugB-protein complex= 1.4*10^-6M

At equilibrium, concentration of B= 2*10^-6-1.4*10^-6= 0.6*10^-6M

At equilibrium, concentration of protein= 1.72*10^-6-1.4*10^-6=0.32*10^-6M

KC for drug-B= [Drug-B protein complex]/[Drug-B] [Protein]= 1.4*10^-6/(0.32*10^-6*0.6*10^-6)=7.3*10⁶