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Solution
Part1:
1. Jovo Progromming JAVA PROGRAMMING
   String n1,n2,n3;
    n1=\"Java Programming\";
    n2=n1.toUpperCase(); //JAVA PROGRAMMING
    n3=n1 + \" \" + n2; // Java Programming JAVA PROGRAMMING
    System.out.println(n3.replace(\'a\',\'o\')); // Jovo Progromming JAVA PROGRAMMING
   
2. num3=Math.sqrt(num1+num2);
3. lemon
 apple
           
 int num=57, max=35;
 if(num>=max*2) //condition evaluates to false. So \'if\' block won\'t be entered.
    System.out.println(\"orange\");
 System.out.println(\"lemon\");
 System.out.println(\"apple\");
Part 2:
Assignment3.java:
import java.util.Scanner;
public class Assignment3 {
public static void main(String args[]){
   Scanner sc=new Scanner(System.in);
    System.out.println(\"Please enter a string\");
    String string1=sc.nextLine();
    //First string is read in string1 variable
   
    System.out.println(\"Please enter another string\");
    String string2=sc.nextLine();
    //Second string is read in string2 variable
   if(string1.length()%2==0)
        //If number of characters in first String is divisible by 2, it\'s even
        System.out.println(\"The first string\'s length is even\");
    else
        //If number of characters in first String is not divisible by 2, it\'s odd
        System.out.println(\"The first string\'s length is odd\");
  
    if(string2.length()%2==0)
        //If number of characters in second String is divisible by 2, it\'s even
        System.out.println(\"The second string\'s length is even\");
    else
        //If number of characters in second String is not divisible by 2, it\'s odd      
        System.out.println(\"The second string\'s length is odd\");
  
   
    if(string1.equals(string2)) //It checks if 2 strings are equal
        System.out.println(\"The two strings are same\");
    else
        System.out.println(\"The two strings are different\");
       
   if(string1.compareTo(string2)>0) //if string1>string2, positive value is returned
        System.out.println(\"The first string is lexically larger\");
    else if(string1.compareTo(string2)<0) //if string1<string2, negative value is returned
        System.out.println(\"The second string is lexically larger\");
    else   //if strings are equal, 0 is returned
        System.out.println(\"The strings are lexically equal\");
   //charAt function gives the first character of the String
    System.out.println(\"The first character of the first string is \"+ string1.charAt(0));
    System.out.println(\"The first character of the second string is \"+ string2.charAt(0));
   
    // \'+\' concatenates value of 2 strings
    System.out.println(\"The concatenation of the two strings is \"+ string1+string2);
   
    // toUpperCase() function returns the String in Upper case.
    System.out.println(\"The first string using uppercase letters: \"+ string1.toUpperCase());
    System.out.println(\"The second string using uppercase letters: \"+ string2.toUpperCase());
   }
 }
 Test Case 1:
 Please enter a string
 carrots
 Please enter another string
 Potatoes
 The first string\'s length is odd
 The second string\'s length is even
 The two strings are different
 The first string is lexically larger
 The first character of the first string is c
 The first character of the second string is P
 The concatenation of the two strings is carrotsPotatoes
 The first string using uppercase letters: CARROTS
 The second string using uppercase letters: POTATOES
 Test Case 2:
 Please enter a string
 cabbage
 Please enter another string
 cabbage
 The first string\'s length is odd
 The second string\'s length is odd
 The two strings are same
 The strings are lexically equal
 The first character of the first string is c
 The first character of the second string is c
 The concatenation of the two strings is cabbagecabbage
 The first string using uppercase letters: CABBAGE
 The second string using uppercase letters: CABBAGE
Note: Please write the header information(assignment number, lab letter, name, etc) in comments.



