How many ways are there for 6 men and 4 women to stand in a
How many ways are there for 6 men and 4 women to stand in a line so that no two women stand next to each other (First, determine where the men are standing and then consider the women)
Solution
6 men and 4 women
no two women stand next to each other
Hence first arrange all 6 men in a line
This can be done in 6! ways
Now there will be 7 places for women including two extreme ends
5 women can be placed in 7 places in 7C5 ways
Hence total ways = 6! (7C5)
= 720(21)
= 15120
