The answer for Part A 43 lbs Part B 37 lbs Part C 39 lbs I j

The answer for

Part A) 43 lbs

Part B) 37 lbs

Part C) 39 lbs

I just want to know how to get these answers

Thanks :)

Solution

Ax is zero.

Balancing forces in horizontal direction,

Bx + Ax - Tcos30 = 0

Bx = Tcos30 - 0   

Bx = T cos30 .............(i)


now balancing momet about hinge point B:

(8/2 * 80) - (8 * Tsin30) - (4 * Tcos30) = 0

2Tsin30 + Tcos30 = 80

T = 80 / 1.866 = 42.87 lbs ........Ans(A)

(B) from (i)

Bx = Tcos30 = 42.87 cos30 = 37.13 lbs ......Ans

(c)balancing forces in vertical,

Fy - mg + Tsin30 = 0


Fy = 80 - (42.87 sin30) = 58.5 lbs ........Ans

The answer for Part A) 43 lbs Part B) 37 lbs Part C) 39 lbs I just want to know how to get these answers Thanks :)SolutionAx is zero. Balancing forces in horizo

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