1 Given the amounts find the limiting reactant for cach reac

1. Given the amounts, find the limiting reactant for cach reaction mixture. Some balancing may be nocessary! a) 60 mL of .O M NaO is added to 12.0 mL of 0.50 M H:S0 b) 50.0 mL of 1.0MHCl( is added to 1853 gof Ca(O c) 120 mL of 0.50 M HNOinp is added to 120ml of LO M NaOH 2. Write the molecular, ionic and net ionic equations for all the acid base reactions in the question above CHE-J2SI Experiment Student Name: Insfracter Name 3. Given the following data: 0.025 0.050 0.073 1.0 1.9 2.9 Make an estimation to predict the result when 0.200 moles of neactant are added. Explain

Solution

Q1)

a) 2NaOH(aq) + H2SO4 (aq) ---------------> Na2SO4 (aq) + 2H2O(l)

6x 1.0 =6 12x0.5 = 6 0 0 initial mmoles

0 3 3 - after reaction

AS NaOH is completely consumed ,NaOH is the limiting reagent

b) 2HCl(aq) + Ca(OH)2(s) ------------------> CaCl2 (aq) + 2H2O(l)

50x1.0 = 50 [ 1.853/74]x10³ =   25.04 0 0 initial mmoles

0 0.04 25 - after reaction

AS all the HCl is consumed HCl is the limiting reagent

C) HNO3 (aq) + NaOH (aq) ------------> NaNO3(aq) + H2O(l)

12x0.5 =6 12x1 =12 0 0 initial mmoles

0 6 6 - after reaction

Thus HNO3 which is consumed completely is the limiting reagent.

2) a)

2NaOH(aq) + H2SO4 (aq) ---------------> Na2SO4 (aq) + 2H2O(l) Molecular

2Na+ + 2OH- + 2H+ +SO4-2 --------------> 2Na+ + SO4-2 + 2 H2O (l) total IOnic

  2OH- + 2H+ ------------> 2 H2O(l) net ionic equation

b)

2HCl(aq) + Ca(OH)2(s) ------------------> CaCl2 (aq) + 2H2O(l)

  

Ca+ + 2OH- + 2H+ +2Cl- --------------> Ca+ + 2Cl- + 2 H2O (l) total IOnic

2OH- + 2H+ ------------> 2 H2O(l) net ionic equation

c)

HNO3 (aq) + NaOH (aq) ------------> NaNO3(aq) + H2O(l) molcular

OH- + Na+ + H+ +NO3- ------------> H2O(l) + Na+ +NO3-total ionic equation

OH- + H+ ------------> H2O(l) net ionic equation