For the reaction of CaOH dissolving in water indicate which

For the reaction of Ca(OH), dissolving in water indicate which direction the reaction will shift for each change to the equilibrium mixture Ca(OH),(s)-ca\"(aq) + 2 OH {aq) Keg-1.3x 10\" a. Adding more water? b. Adding more solid Ca(OH), c. Adding solid Ca(NO3), to the reaction d. Adding aqueous HCI to the solution e. Adding aqueous KOH to the solution

Solution

(a)

Adding of water does not alter the equilibrium position as pure liquids do not change their concentration.

(b)

Adding of solid Ca(OH)₂ also does not alter the equilibrium position as the pure solids do not change their concentration.

(c)

Ca(NO₃)₂ will undergo the following dissociation.

Ca(NO₃)₂ (aq.) -----------> Ca²⁺ (aq.) + 2 NO₃^- (aq.)

So, it will increase the concentration of Ca²⁺ ions, i.e. roducts and hence shifts the equilibrium position towards left side i.e. back ward direction.

(d)

Addition of HCl, release the H⁺ ions which react with OH^- ions of euilibrium as follows,

H⁺ (aq.) + OH^- (aq.) -----------> H₂O (l)
So, it will remove the OH- ions from euilibrium causing decrease in concentration of products and hence equilibrium position is shifted towards right side i.e. forward direction.

(e)

Added KOH will undergo following dissociation,

KOH (aq.) ------------> K⁺ (aq.) + OH^- (aq.)

So, it will increase the concentration of products and hence the equilibrium position is shifted towards left side i.e. back ward direction.