Three machines turn out all the products in a factory with t

Three machines turn out all the products in a factory, with the first machine producing 15% of the products, the second machine 15%, and the third machine 70%. The first machine produces defective products 19% of the time, the second machine 17% of the time and the third machine 11% of the time. What is the probability that a non-defective product came from the second machine? (Round your answer to four decimal places.)

Solution

Let the total number of product be 100
2nd machine produces = 15 products
defective product from 2nd machine = 17% of 15 =2.55
non defective product from 2nd machine = 15 - 2.55 = 12.45

probability of non defective product from 2nd machine= 12.45/15
                                                                                     = 0.8300