In C Code a program that will print the numbers from 1 to 1

(In C++ ) Code a program that will print the numbers from 1 to 15, however when the number is a multiple of 3 it will print \"Whiz\". If the number is a multiple of 5, print \"Bang.\" If the number is a multiple of 3 and 5 print \"Whiz Bang\"

Solution

#include<iostream>
#include<conio.h>
using namespace std;
int main()
{


    for(int i=1;i<=15;i++)
    {

        if(i%3==0&&i%5==0) //for number both divisible by both 5 and 3.
        {
        cout<<\"Whiz Bang\"<<endl;
        break;
        }

        if(i%3==0) {        //for number disible by 3.       
        cout<<\"whiz\"<<endl;

        }

        if(i%5==0){             //for number disible by 3.
        cout<<\"Bang\"<<endl;
        }

        if(i%3!=0&&i%5!=0)     //for number not divisible by 5 or 3.
        {
        cout<<i<<endl;
        }

    }
getch();
}

// If the Answer was satisfying feedback is appreciated, & do comment if not correct or not as u expected.. thanx..

(In C++ ) Code a program that will print the numbers from 1 to 15, however when the number is a multiple of 3 it will print \

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