The onetoone functions g and h are defined as follows g 5 6

The one-to-one functions g and h are defined as follows. g = {(-5, -6), (3, -2), (4, 1), (6, -5)} h(x) = 9x + 4 Find the following. g^-1 (-5) = h^-1 (x) = (h^-1 compositefunction h) (-1) =

Solution:

SInce g(6) =-5

g^-1(-5) = 6

now

h(x) = 9x+4

y = 9x+4

substitue y =x

x = 9y+4 and solve for y

y = (x-4)/9

h^-1(x) = (x-4)/9

Now

(h^-1oh )(x)= h^-1(h(x))

= h^-1(9x+4)

= 9(x-4)/9 + 4

= x

therefore (h^-1oh)(-1)= -1

answer: -1

$The one-to-one functions g and h are defined as follows. g = {(-5, -6), (3, -2), (4, 1), (6, -5)} h(x) = 9x + 4 Find the following. g^-1 (-5) = h^-1 (x) = (h^-$

The onetoone functions g and h are defined as follows g 5 6

Solution

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