For the reaction 2AgBg2Cg a reaction vessel initially contai

For the reaction 2A(g)B(g)+2C(g), a reaction vessel initially contains only A at a pressure of PA=250mmHg.

At equilibrium, PA=71mmHg.

Calculate the value of Kp. (Assume no changes in volume or temperature.)

Solution

2A (g) ---------------- B(g) + 2 C(g)

250mm                  0           0

-2x                        +x         +2x

250 -2x                 +x            +2x

At equilibrium

PA= 71mm

250 - 2x = 71

2x= 179

x= 89.5 mm

at equilibrium

partial pressure of B= PB= 89.5 atm

Partial pressure of C= 2x = 2x(89.5) = 179 atm

Kp = PB xP^2C/P^2A

Kp = (89.5) x(179)^2/(71)^2 =568.87

Kp = 568.87