I am doing analytical chemistry lab of preparing standard ac

I am doing analytical chemistry lab of preparing standard acid and base (titration)

I need the sample calculation of Naoh and HCL molarity each for their own 3 trials

Data for Naoh (I have to prepare Naoh by my self I believe molarity is 0.1)

trial KHP   Naoh volume Naoh molarity

1 0.51g 33.82 mL ?

2 0.51g 30.64 mL ?

3 0.51g 31.12 mL ?

Data for HCL (I have to prepare HCL by my self I made a mistake by only use 500ml water instead 1000. I believe molarity is 0.2)

trial Na2CO3 HCL volume HCL molarity

1 0.13g 13.1 ?

2 0.13g 11.59 ?

3 0.13 9.87 ?

Please show calculations for all the molarity. Big thanks

Solution

trial KHP   NaOH volume NaOH molarity

1 0.51g 33.82 mL 0.075 M

2 0.51g 30.64 mL 0.082 M

3 0.51g 31.12 mL 0.0803 M  

Molarity = no. of moles of solute /volume in liters

Molarity = no. of moles of solute /volume in mili liters (1000)

no. of moles of solute = given mass / molar mass

KHP (Potassium hydrogen phthalate) molar mass = 204.2 g/mol

Trial 1 ; no. of moles of solute = 0.51 / 204.2 = 0.0025 M

Molarity = no. of moles of solute /volume in mili liters (1000)

Molarity = 0.0025 /33.82 ml (1000) = 7.4 (10-5)(1000) = 0.000075 (1000) = 0.075 M

Trial 2 ;Molarity = 0.0025 /30.64 ml (1000) = 8.2 (10-5) (1000) = 0.000082 (1000) = 0.082 M

Trial 3 ;Molarity = 0.0025 /31.12 ml (1000) = 8.03 (10-5) (1000) = 0.0000803 (1000) = 0.0803 M

Data for HCL (I have to prepare HCL by my self I made a mistake by only use 500ml water instead 1000. I believe molarity is 0.2)

trial Na2CO3 HCl volume HCl molarity

1 0.13g 13.1 0.092 M

2 0.13g 11.59 0.0103 M

3 0.13g    9.87 0.121 M

molar mass of Na2CO3= 106 g/mol

Trial 1 ; no. of moles of solute = 0.13 / 106 = 0.0012 M

Molarity = no. of moles of solute /volume in mili liters (1000)

Molarity = 0.0012 /13.10 ml (1000) = 9.2 (10-5)(1000) = 0.000092 (1000) = 0.092 M

Trial 2 ;Molarity = 0.0012 /11.59 ml (1000) = 1.03 (10-5) (1000) = 0.0000103 (1000) = 0.0103 M

Trial 3 ;Molarity = 0.0012 /9.87 ml (1000) = 1.21 (10-4) (1000) = 0.000121 (1000) = 0.121 M

I am doing analytical chemistry lab of preparing standard acid and base (titration) I need the sample calculation of Naoh and HCL molarity each for their own 3
I am doing analytical chemistry lab of preparing standard acid and base (titration) I need the sample calculation of Naoh and HCL molarity each for their own 3

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site