Even obtained the following absorbance data Concentration nM
Even obtained the following absorbance data:
Concentration (nM)
absorbance
13.0
.095
16.2
.143
19.4
.205
22.6
.241
25.8
.312
A graph of this data revealed the line equation Is y=.0166x-.1223 with an R^2 square value of .99234
a. a. Evan measures an unknown solution with an absorbance of .448. What is the concentration of the solution?
b. b. Evan takes 1.0 ml of a solution and dilutes it to 50.0ml. The absorbance is .192. What is the concentration of the original solution?
\\plplease show work!!!!
| Concentration (nM) | absorbance |
| 13.0 | .095 |
| 16.2 | .143 |
| 19.4 | .205 |
| 22.6 | .241 |
| 25.8 | .312 |
Solution
a) given y= 0.448 , therfore from y=.0166x-.1223, x= 34.355 nM
b) again, y=0.192 , therfore x=18.93M, therfore concentration of original solution = 50*18.93 = 946.5 nM
