The Spanish club is arranging a trip to a Mexican restaurant
The Spanish club is arranging a trip to a Mexican restaurant in a nearby city. Those who go must share the $160 cost of using a school bus for the trip. The restaurant’s buffet costs $5 per person. How many students must sign up for this trip in order to limit the cost to $13 per student?
Please define your variables and write the equation you used as a part of the solution. Use algebra to solve the problem. Solutions that involve trial-and-error will not earn credit.
Here is a similar problem:
The Spanish club is arranging a trip to a Mexican restaurant in a nearby city. Those who go must share the $60 cost of using a school bus for the trip. The restaurant’s buffet costs $5 per person. How many students must sign up for this trip in order to limit the cost to $10 per student?
Defining the variable:
Suppose we need n students to limit the cost to $10 per student. The total amount the students will bring = $10n.
The total cost of the trip = $(60+5n)
Setting up the equation:
10n = 60+5n
Solving the equation:
10n = 60+5n
Þ 10n - 5n = 60
Þ 5n = 60
Þ n = 60/5 = 12
Ans: 12 people must sign up.
Solution
Let n students are needed to limit the cost to $13 per student.
That implies
The total amount will be =$13n
The total cost of the trip will be = $(160+5n) {because $160 is fixed for the school bus and $5 is restaurant’s buffet cost per person}
Now
Equating both the conditions
We get the equation
13n= 160+5n
Subtract 5n from both sides
8n=160
Divide by 8 on both sides
n=160/8
n=20 ( answer is 20 students must sign up )
