number 11 Let R be the relation in the set of natural number
number 11
Solution
For the relation to be an equivalence relation, it must be reflexive, symmetric and transitive
Relation is said to be reflexive if (x,x) belongs to N
Since (x-x) = 0, which is divisible by 2, hence the relation is reflexive in nature
Relation is said to be symmetric if (x,y) belong to N, then (y,x) must also belong to N
Since (x-y) is divisible by 2, hence we can (x-y) = 2k
(y-x) = -(x-y) = -2k = 2(-k) = 2k1, hence (y-x) also divides 2. therefore the relation is symmetrix in nature
Relation is said to be transitive if (x,y) and (y,z) belongs to N, then it implies (x,z) belongs to R
(x-y) = 2k1
(y-z) = 2k2
(x-z) = (x-y) + (y-z) = 2k1 + 2k2 = 2(k1+k2) = 2k3
Hence (x-z) is divisible by 2
Therefore relation is transitive in nature
Since relation is reflexive, symmetric and transitive, it is an equivalence relation
