A cashier has 46 bills made up of ones fives and twenties Th

A cashier has 46 bills, made up of ones, fives and twenties. The number of twenties is twenty less than the combined number of fives and ones. The total value of the money is $353. How many of each bill are there? ______________________________________

Solution

Let there are x number. Of one\'s,y number of fives and z number of twenties by question x+y+z =46--(1) x+y-z=20---(2) x+5y+20z=353--(3) (1)+(2)gives 2x+2y=66 or x+y=33--(4) equation (2) into 20+ equation(3) gives21x+25y=753--(5) equation(4)into25and if(5) is subtracted from it then 4x=825-753 or x=72/4=18 , from equation(4) 18+y=33 or y=33-18=15 ,from equation(1) 18+15+z=46. or z=46-33=13. No of bills is18 no of bills of five s 15. No of bills of twenties 13 ans.