42 Picture for 4 24 Note hypotenuse 2427225 a sin 2t 7 symbo

4(2). Picture for 4. 24 Note hypotenuse /242+72-25 (a) sin 2t 7 symbols, chk-2 (b) cos(t/2) 5 or 6 symbols, chk-25

Solution

sin t=opposite/hypotenuse=7/25

cos t= adjacent/hypotenuse =24/25

sin(2t) = sin t cos t=2(7/25)(24/25)=336/625

cos(t/2) = sqrt((1+cos t)/2) = sqrt(1 + 24/25)/2)

=sqrt(49/50) = (7/5)(1/sqrt2)

=7(sqrt2)/10