Let the quadratic function f be defined as fx 4x x2 Comput

Let the quadratic function f be defined as f(x) = 4x - x^2. Compute the following functional values. (a) f(-2) (b) f(0) (c) f(0.001) (d) For what values of x is f(x) = 4?

Solution

Dear Student Thank you for using Chegg !! f(x) = 4x - x^2 a) f(-2) = = 4 (-2) - (-2)^2 = -12 Solution b) f(0) = 4(0) - (0)^2 = 0 Solution c) f(0.001) = 4(0.001) - (0.001)^2 = 4*0.001 - 0.001^2 = 0.003999 Solution d) f(x) = 4 => 4x - x^2 = 4 x^2 - 4x + 4 = 0 (x-2)^2 = 0 x=2 Solution