calculate the hydrogen ion concentration in mol for the foll
calculate the hydrogen ion concentration in mol/ for the following solutions
2.42
11.21
6.96
15.00
Solution
PH=-log[H+] [H+]=10^(-Ph) 1)[H+]=10^(-2.62) 2)[H+]=10^(-11.21) 3)[H+]=10^(-6.96) 4)[H+]=10^(-15) But in the 4th case it is smaller than [H+] concentration of water...So there will be a equilibrium and hence the [H+]=10^(-14) ionic product of water...![calculate the hydrogen ion concentration in mol/ for the following solutions 2.42 11.21 6.96 15.00Solution PH=-log[H+] [H+]=10^(-Ph) 1)[H+]=10^(-2.62) 2)[H+]=10 calculate the hydrogen ion concentration in mol/ for the following solutions 2.42 11.21 6.96 15.00Solution PH=-log[H+] [H+]=10^(-Ph) 1)[H+]=10^(-2.62) 2)[H+]=10](/WebImages/42/calculate-the-hydrogen-ion-concentration-in-mol-for-the-foll-1129133-1761602811-0.webp)