A B C 66 B 2 5A C 2B 4A B SolutionA B C 66 1 B 2

A + B + C = 66

B = 2 + 5A

C = 2B + 4A

B = ?

A + B + C = 66 ----(1)

B = 2 + 5A -----(2)

C = 2B + 4A ----(3)

substitute value of A from equa (2)

A = (B -2)/5

C = 2B +4(B -2)/5

= 2B + 4B/5 - 8/5

= (14B -8)/5

(B -2)/5 + (14B -8)/5 + B = 66

( B -2 +14B -8 +5B)/5 = 66

20B -10 = 66*5

20B = 340

B = 17